If a planer removes up to 1/16 inch per pass, how many passes are required to remove 9/16 inch from stock?

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Multiple Choice

If a planer removes up to 1/16 inch per pass, how many passes are required to remove 9/16 inch from stock?

Explanation:
To remove a total of 9/16 inch with each pass taking off up to 1/16 inch, you divide the total amount to be removed by the amount removed per pass. (9/16) ÷ (1/16) equals 9. So nine passes are needed. This assumes you’re taking the maximum allowed each time; since 9/16 is exactly a multiple of 1/16, you can reach the target with nine equal passes. If any pass removes less than 1/16, you’d still need at least nine passes, possibly more.

To remove a total of 9/16 inch with each pass taking off up to 1/16 inch, you divide the total amount to be removed by the amount removed per pass. (9/16) ÷ (1/16) equals 9. So nine passes are needed. This assumes you’re taking the maximum allowed each time; since 9/16 is exactly a multiple of 1/16, you can reach the target with nine equal passes. If any pass removes less than 1/16, you’d still need at least nine passes, possibly more.

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